lab report

The natural law of conversation of heat energy Objective: To collect calefactive and dusty liquid together and predict the temperature of the pastiche. Equipment/Materials: Styrofoam transfuse, galvanic pile scale, Procedures: 1.Take a dry Styrofoam instill mass the transfuse and record. 2.Pour close to 50 mL to 60 mL mothy muddle in the cup. commode the cup + shivery H2 O. Record. 3.Take the temperature of moth-eaten H2 O and record. 4.Take about 90 mL to 100 mL of acid irrigate. 5.Record the temperature of hot H2 O. 6.Mix the hot water with cold water. Stir quiet and take the temp of the diverseness. 7.Record the mass of the cup + cold H2 O+ hot H2 O. 8.Clean up work area. information: pack of Styrofoam = 3.9g Temperature of cold water = 21̊C jackpot of Styrofoam cup + cold water = 52.9g Temperature of hot water = 72̊C push-down stack of Styrofoam cup + cold water + hot water = 142.1g Temperature of the mi xture = 51̊C Calculations: 1.Calculate the mass of cold water. Mass of cup + cold water mass of Styrofoam 52.9g 3.9g = 3.0g 2.Calculate the mass of hot water. Mass of Styrofoam cup + cold water + hot water - Mass of cup + cold water 142.1g 52.9.9g = 89.2g 3.Calculate the temperature of the mixture by applying the law of converstion of heat and energy: (m ∆T Cp)cold water =(m ∆T Cp)hot water (49.0g)(x-21)̊C (4.184 J/g ̊C) = 89.2g (72-x)̊C (4.184 J/g ̊C) 49.0x 1029 = -89.2x + 6422.4 +89.2x +89.2x 138.

2x 1029 = 0 + 6422.4 +! 1029 +1029__ 0 7451.4 138.2x= 7451.4 138.2 138.2 X=53.9̊C 4. Find the % error. (Real #) - ( your #) x 100 = % error (Real #) (53.9̊C) - (51̊C) x 100 = 5.3% (53.9̊C) Conclusion: The share error in this experiment was 5.3%. The reasons for experimental errors are: light up disadvantage to the surroundings. ...If you want to get a full essay, articulate it on our website: BestEssayCheap.com

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